BID | LID
1 2
1 5
1 8
1 11
2 5
2 7
3 11
(BID links to a proper table with stuff)
Help
:C
I want a query which, when passed *two* different "LIDs" will return with all the BIDs that have both of those.
So.. uh..
SELECT * FROM BUM
:@ WHERE (lid = *2* AND lid = *8*)
Would return BID /1/. As it is against both 2 and 8.
-
I can't think of a better way to explain it
:( And I can't think of what to Google for XD ASK ME QUESTIONS AND WE WILL DETERMINE WHAT I MEAN
:$